Sort a Python dictionary by value (Python Dictionary Comprehension)

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In python, dictionary objects are orderless, there is no way you could sort a dictionary 

in place like you could do to a list. But you could get a representation of a dictionary,

and use an ordered data type to represent sorted values, such as a list of tuples.

For instance,

d = {'a':15, 'b':6, 'c':33, 'd':13}

sorted_d = sorted(d.items(), key=lambda item:item[1])

dict(sorted_d)

{'b': 6, 'd': 13, 'a': 15, 'c': 33}

or

import operator

sorted_d = sorted(d.items, key=operator.itemgetter(1))

dict(sorted_d)

{'b': 6, 'd': 13, 'a': 15, 'c': 33}

In Python 3.6+, we could use dictionary comprehension:

{k:v for k,v in sorted(x.items(), key=lambda item:item[1])}

{'b': 6, 'd': 13, 'a': 15, 'c': 33}


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